Java program to check for Pronic Number (Heteromecic Number)
Java program to input a number and check whether it is a pronic number (heteromecic number) or not.
Question:
Write a Program in Java to input a number and check whether it is a Pronic Number or Heteromecic Number or not.
Pronic Number : A pronic number, oblong number, rectangular number or heteromecic number, is a number which is the product of two consecutive integers, that is, n (n + 1).
The first few pronic numbers are: 0, 2, 6, 12, 20, 30, 42, 56, 72, 90, 110, 132, 156, 182, 210, 240, 272, 306, 342, 380, 420, 462 … etc.
Programming Code:
Java
/**
* The class HarshadNumber inputs a number and checks if it a Pronic Number or not
* @author : www.guideforschool.com
* @Program Type : BlueJ Program - Java
*/
import java.util.*;
class PronicNumber
{
public static void main(String args[])
{
Scanner sc = new Scanner(System.in);
System.out.print("Enter a number : ");
int n = sc.nextInt();
int flag = 0;
for(int i=1; i<=n; i++)
{
if(i*(i+1) == n)
{
flag = 1;
break;
}
}
if(flag == 1)
System.out.println(n+" is a Pronic Number.");
else
System.out.println(n+" is not a Pronic Number.");
}
}Alternate Programming Code:
Java
/**
* The class HarshadNumber inputs a number and checks if it a Pronic Number or not
* @author : www.guideforschool.com
* @Program Type : BlueJ Program - Java
*/
import java.util.*;
class PronicNumber
{
public static void main(String args[])
{
Scanner sc = new Scanner(System.in);
System.out.print("Enter a number : ");
int n = sc.nextInt();
int k = (int)(Math.sqrt(n));
if(k*(k+1)==n)
System.out.println(n+" is a Pronic Number.");
else
System.out.println(n+" is not a Pronic Number.");
}
}Output:
Plain
Enter a number : 110
110 is a Pronic Number.
Enter a number : 73
73 is not a Pronic Number.
Enter a number : 342
342 is a Pronic Number.
Enter a number : 15
15 is not a Pronic Number.